For the circuit shown, with R_{1 }= 1.0 Ω, R_{2 }= 2.0 Ω, E_{1 }= 2 V and E_{2 }= E_{3 }= 4 V, the potential difference between the points ‘a’ and ‘b’ approximately (in V):

This question was previously asked in

JEE Mains Previous Paper 1 (Held On: 08 Apr 2019 Shift 1)

Option 4 : 3.3

JEE Mains Previous Paper 1 (Held On: 12 Apr 2019 Shift 2)

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90 Questions
360 Marks
180 Mins

**Concept: **

Applying parallel combination of batteries.

Equivalent emf between A and B is

\({{E}_{eq}}=\frac{\frac{{{E}_{1}}}{2{{R}_{1}}}+\frac{{{E}_{2}}}{{{R}_{2}}}+\frac{{{E}_{3}}}{2{{R}_{1}}}}{\frac{1}{2{{R}_{1}}}+\frac{1}{{{R}_{2}}}+\frac{1}{2{{R}_{1}}}}\)

**Calculation:**

\(\Rightarrow {{E}_{eq}}=\frac{\frac{2}{2}+\frac{4}{2}+\frac{4}{2}}{\frac{1}{2}+\frac{1}{2}+\frac{1}{2}}\)

\(\Rightarrow {{E}_{eq}}=\frac{\frac{10}{2}}{\frac{3}{2}}\)

\(\Rightarrow {{E}_{eq}}=\frac{10}{3}\)

∴ E